Solutions to Practice Problems – Chapter 22
1
a) NPV of First Stage Project = 40/(.18 - .09) – 475 = -30.56 billion
b)
Expected time 3 NPV of second stage project = 100/(.18 - .09) – 1250 = 1111.11
– 1250 = -138.89 billion
c)
For the decision tree approach, we consider the actual time 3 outcomes for the
second stage project:
|
Prob. |
PV3 |
NPV
at time 3 |
Action |
|
0.5 |
1111.11
+ 586 = 1697.11 |
1697.11
– 1250 = 447.11 |
Accept
project |
|
0.5 |
1111.11
- 586 = 525.11 |
525.11
– 1250 = -724.89 |
Reject
project |
So
with a probability of .5, we would end up with a time 3 NPV of 447.11 billion. The value today of this investment opportunity is then
.5*447.11/(1.18^3) = 136.06 billion
The total NPV of both projects together = -30.56 + 136.06 = 105.51 billion => we would accept the project today
d) The second stage project is a call option on the time 3 PV of the project’s future cashflows, with an exercise price of $1250 million.
Maturity = 3 years
Annual standard deviation = 50%
Rf = 11% per year
X = $1250 billion
P0 = the value today (three years before maturity) of the project’s exp. cashflows
=1111.11/(1.18^3) = $676.26 billion
d1
= { ln (676.26/1250) + (.11 + .5*(.5^2))*3}/{0.5*(3^0.5)} = 0.1047
d2
= 0.1047 - 0.5*(3^0.5) = -0.7613
N(d1)
= 0.53984
N(d2)
= 0.24197
C
= 676.26*0.54381 - (1250
* e-.11*3 *0.22663) = 367.7551 – 203.6621 = 147.62
Total
NPV of project = -30.56 + 147.62 = 117.07 billion
2
a) NPV of First Stage Project = 6,500/(.12 - .05) – 100,000 = -7,142.86
b)
Need to be careful with the PVs since cashflows start 2 years after the
investment.
Expected
time 5 PV of second stage project’s cashflows = 20,000/(.12 - .05) =
314,285.71
Expected
time 4 NPV of second stage project = 314,285.71/1.12 – 300,000 = -19,387.76
c)
For the decision tree approach, we consider the actual outcomes for the second
stage project:
|
Prob. |
PV5 |
NPV
at time 4 |
Action |
|
.4 |
314,285.71
+ 60,000 = 374,285.71 |
374,285.71/1.12
– 300,000 = 34,183.67 |
Accept
project |
|
.6 |
314,285.71
- 40,000 = 274,285.71 |
274,285.71/1.12
– 300,000 < 0 |
Reject
project |
So
with a probability of .4, we would end up with a time 4 NPV of 34,183.67.
The value today of this investment opportunity is then
.4*34,183.67/(1.12^4) = 8,689.74
The total NPV of both projects together = -7,142.86 + 8,689.74 = 1,546.88 => we would accept the project today
d) The second stage project is a call option on the time 4 PV of the project’s future cashflows (since the second stage project involves investing at time 4), with an exercise price of $300,000.
Maturity = 4 years
Annual standard deviation = 12.2853%
Rf = 9% per year
X = $300,000
P0 = the value today (three years before maturity) of the project’s exp. cashflows
=314,285.71/(1.12^5) = $178,334.15
d1
= { ln (178,334.15/300,000) + (.09 + .5*(0.122853^2))*4}/{0.122853*(4^0.5)} =
-0.5288
d2
= -0.5288 - 0.122853*(4^0.5) = -0.7745
N(d1)
= 0.29807
N(d2)
= 0.22065
C
= 178,334.15*0.29807 - (300,000
* e-.09*4 *0.22065) = 53,156.06 – 46,182.68 = 6,973.38
Total
NPV of project = -7,142.86
+ 6,973.38 = -169.48
3)
NPV of First Stage Project = 1.25/(.12 - .04) – 15 = 0.625 million
Second
Stage Project:
The second stage project is a call option on the time 3 PV of the project’s future cashflows, with an exercise price of $25 million.
Maturity = 3 years
Annual standard deviation = 40%
Rf = 6% per year
X = $25m
P0 = the value today (three years before maturity) of the project’s exp. cashflows
= [1.8/(.12 - .04)]/(1.12^3) = $16.015 million
d1
= { ln (P0/X)
+ (R + 0.5 s2)*
T}/{s
Ö
T }
= { ln (16.015/25) + (.06 + .5*(.4^2))*3}/{0.4*(3^0.5)} = -0.037
d2
= d1 - s
Ö
T = -0.037 - 0.4*(3^0.5) = -0.729
N(d1)
= 0.48404
N(d2)
= 0.23270
C
= P0
N(d1) - X e-RT N(d2) = 16.015*0.48404 -
(25 *
e-.06*3 *0.2327)
= 7.752 – 4.859 = 2.893
Total
NPV of project = 0.625 + 2.893 = 3.518 million
4
a) If you take the project today, NPV = 16/.15 – 100 = 6.67 million
The
decision tree approach would compute the NPV if you wait as follows:
|
Prob. |
PV1 |
NPV
at time 1 |
Action |
|
.5 |
18/.15
= 120 |
120
– 100 = 20 |
Accept
project |
|
.5 |
14/.15
= 93.33 |
negative |
Reject
project |
So
with a probability of .5, we would end up with a time 1 NPV of 20.
The value today of this investment opportunity is then .5*20/1.15 = 8.696
million. Therefore, it is better to
wait rather than take the project today.
b) Under the option pricing approach, if we wait, the project is a call option on the time 1 PV of the project’s future cashflows.
Maturity = 1 year
Rf = 7.5% per year
X = $100 million
P0 = the value today of the project’s exp. cashflows = (.5*120 + .5*93.33)/1.15 = 92.754 million
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.5 |
120 |
120/92.754
– 1 = 29.375% |
|
.5 |
93.33 |
93.33/92.754
– 1 = 0.625% |
Variance of annual return = Prob of R1*[ R1 - E(R)]2 + Prob of R2*[ R2 - E(R)]2
=
.5*(.29375-.15)2 + .5*(.00625-.15)2 = .0207
Annual
standard deviation = 14.38%
d1
= { ln (92.754/100) + .075 + .5*(0.1438^2)}/{0.1438} = 0.0703
d2
= 0.0703 - 0.1438 = -.0734
N(d1) = 0.52791
N(d2) = 0.47209
C
= 92.754*0.52791 - (100
* e-.075 *0.47209) = 48.966 – 43.798 = 5.168 million.
This
time it is better to take the project today.
5
a) If you take the project today, NPV = 98.6/.13 – 750 = 8.462 million
The
decision tree approach would compute the NPV if you wait as follows:
|
Prob. |
PV1 |
NPV
at time 1 |
Action |
|
.4 |
110/.13
= 846.154 |
846.15
– 750 = 96.15 |
Accept
project |
|
.6 |
91/.13
= 700 |
negative |
Reject
project |
So
with a probability of .4, we would end up with a time 1 NPV of 96.15.
The value today of this investment opportunity is then .4*96.15/1.13 =
34.037 million. Therefore, it is
better to wait rather than take the project today.
b) Under the option pricing approach, if we wait, the project is a call option on the time 1 PV of the project’s future cashflows.
Maturity = 1 year
Rf = 4% per year
X = $750 million
P0 = the value today of the project’s exp. cashflows = (.4*846.154 + .6*700)/1.13 = 671.205 million
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.4 |
846.154 |
846.154/671.205
– 1 = 26.065% |
|
.6 |
700 |
700/671.205
– 1 = 4.290% |
Variance of annual return = Prob of R1*[ R1 - E(R)]2 + Prob of R2*[ R2 - E(R)]2
=
.4*(.26065-.13)2 + .6*(.0429-.13)2 = .0114
Annual
standard deviation = 10.6675%
d1 = { ln (671.205/750) + .04 + .5*.0114}/{0.106675} = -0.6122
d2
= -0.612 - 0.106675 = -0.7189
N(d1) = 0.27094
N(d2) = 0.23577
C
= 671.205*0.27094 - (750
* e-.04 *0.23577) = 181.856 – 169.894 = 11.962 million.
Once
again, it is better to wait than to take the project today.
6
a) If you take the project today, NPV = 41,000/.11 – 365,000 = 7,727.27
The
decision tree approach would compute the NPV if you wait as follows:
|
Prob. |
PV1 |
NPV
at time 1 |
Action |
|
.6 |
45,000/.11
= 409,090.91 |
409,090.91
– 365,000 = 44,090.91 |
Accept
|
|
.4 |
35,000/.11
= 318,181.82 |
negative |
Reject
|
So
with a probability of .6, we would end up with a time 1 NPV of 44,090.91.
The value today of this investment opportunity is then .6*44,090.91/1.11
= 23,832.92.
Therefore,
it is better to wait rather than take the project today.
b) Under the option pricing approach, if we wait, the project is a call option on the time 1 PV of the project’s future cashflows.
Maturity = 1 year
Rf = 4% per year
X = $365,000
P0 = the value today of the project’s exp. cashflows = (.6*409,090.91 + .4*318,181.82)/1.11 = 335,790
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.6 |
409,090.91 |
409,090.91 |
|
.4 |
318,181.82 |
318,181.82 |
Variance of annual return = Prob of R1*[ R1 - E(R)]2 + Prob of R2*[ R2 - E(R)]2
=
.6*(.21829-.11)2 + .4*(-.05244-.11)2 = .0176
Annual
standard deviation = 13.263%
d1
= { ln (335,790/365,000) + .04 + .5*.0176)}/{0.13263} = -0.2610
d2
= -0.261 - 0.13263 = -0.3936
N(d1) = 0.39743
N(d2) = 0.34828
C
= 335,790*0.39743 - (365,000
* e-.04 *0.34828) = 133,453.15 – 122,137.67 = 11,315.48.
Once
again, it is better to wait than to take the project today.
7
a) Under the decision tree approach, the firm will abandon the project at time 1
whenever the PV is less than the abandonment value of $425,000.
So
the expected future cashflows are .25*425,000 + .25*425,000 + .25*440,000 +
.25*500,000 = 447,500
The
value of the project after accounting for the abandonment option = 447,500/.125
– 400,000 = -2,222.22. So, using
the decision tree approach, we wouldn’t accept this project.
b)
Ignoring the option to abandon, the NPV of the project is (.25*390,000 +
.25*410,000 + .25*440,000 + .25*500,00)/1.125 – 400,000 = -13,333.33
The
abandonment option is a one-year put option on the time 1 PV of the project’s
cashflows, with an exercise price equal to the abandonment value of $425,000.
Maturity = 1 year
Rf = 5% per year
X = $425,000
P0 = the value today of the project’s exp. cashflows = 386,666.67
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.25 |
390,000 |
390,000/386,666.67
– 1 = 0.862% |
|
.25 |
410,000 |
410,000/386,666.67
– 1 = 6.034% |
|
.25 |
440,000 |
440,000/386,666.67
– 1 = 13.793% |
|
.25 |
500,000 |
500,000/386,666.67
– 1 = 29.310% |
Variance of annual return = .25*(.00862 -.125)2 + .25*(.06034-.125)2 + .25*(.13793 -.125)2 + .25*(.29310-.125)2 = .0115
Annual
standard deviation = 10.74%
First
we compute the value of a call option:
d1
= { ln (386,666.67/425,000) + .05 + .5*(0.1074^2)}/{0.1074} = -0.3608
d2
= -0.3608 - 0.1074 = -0.4682
N(d1)
= 0.35943
N(d2)
= 0.31919
C
= 386,666.67*0.35943 - (425,000
* e-.05 *0.31919) = 138,979.60 – 129,039.74 = 9,939.86.
The
value of the put is then C - P0 + X e-RT = 9,939.86 –
386,666.67 + 425,000*
e-.05
= 27,545.70.
The
total NPV of the project after taking into account the abandonment option = NPV
without abandonment option + value of abandonment option = -13,333.33 +
27,545.70 = 14,212.36
8
a) Under the decision tree approach, the firm will abandon the project at time 1
whenever the PV is less than the abandonment value of $780 million.
So
the expected future cashflows are .1*780 + .2*780 + .3*800 + .4*900 = 834
million
The
value of the project after accounting for the abandonment option = 834/1.1 –
750 = 8.18 million.
b)
Ignoring the option to abandon, the NPV of the project is (.1*700 + .2*750 +
.3*800 + .4*900)/1.1 – 750 = 745.45 - 750 = -4.55 million
The
abandonment option is a one-year put option on the time 1 PV of the project’s
cashflows, with an exercise price equal to the abandonment value of $780
million.
Maturity = 1 year
Rf = 6% per year
X = $780 million
P0 = the value today of the project’s exp. cashflows = 745.45 million
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.1 |
700 |
700/745.45
– 1 = -6.098% |
|
.2 |
750 |
750/745.45
– 1 = 0.610% |
|
.3 |
800 |
800/745.45
– 1 = 7.317% |
|
.4 |
900 |
900/745.45
– 1 = 20.732% |
The expected return is just the required return of 10%.
Variance of annual return = .1*(-.06098 -.1)2 + .2*(.0061-.1)2 + .3*(.07317 -.1)2 + .4*(.20732-.1)2 = .0092
Annual
standard deviation = 9.58%
First
we compute the value of a call option:
d1
= { ln (745.45/780) + .06 + .5*(0.0958^2)}/{0.0958} = 0.2013
d2
= 0.2013 - 0.0958 = 0.1055
N(d1)
= 0.49601
N(d2)
= 0.49016
C
= 745.45*0.49601 - (780
* e-.06 *0.49016) = 369.75 – 338.02 = 31.73 million.
The
value of the put is then C - P0 + X e-RT = 31.73 –
745.45 + 780*
e-.06
= 20.85 million.
The
total NPV of the project after taking into account the abandonment option = NPV
without abandonment option + value of abandonment option = -4.55 + 20.85 = 16.31
million.
9
a) Under the decision tree approach, the firm will abandon the project at time 1
whenever the PV is less than the abandonment value of $295 million.
So
the expected future cashflows are .25*295
+ .3*295 + .45*333 = 312.10 million
The
value of the project after accounting for the abandonment option = 312.1/1.14
– 240 = 33.77 million.
b)
Ignoring the option to abandon, the NPV of the project is (.25*222 + .3*250 +
.45*333)/1.14 – 240 = 245.92 - 240 = 5.92 million
The
abandonment option is a one-year put option on the time 1 PV of the project’s
cashflows, with an exercise price equal to the abandonment value of $295
million.
Maturity = 1 year
Rf = 6% per year
X = $295 million
P0 = the value today of the project’s exp. cashflows = 245.92 million
Annual standard deviation is computed as follows:
|
Prob. |
PV1 |
Annual
Return |
|
.25 |
222 |
222/245.92
– 1 = -9.727% |
|
.3 |
250 |
250/245.92
– 1 = 1.659% |
|
.45 |
333 |
333/245.92
– 1 = 35.409% |
The expected return is just the required return of 14%.
Variance of annual return = .25*(-0.09727-.14)2 + .3*(.01659 -.14)2 + .45*(.35409-.14)2 = .0393
Annual
standard deviation = 19.82%
First
we compute the value of a call option:
d1
= { ln (245.92/295) + .06 + .5*(0.1982^2)}/{0.1982} = -0.5164
d2
= -0.5164 - 0.1982 = -0.7146
N(d1)
= 0.30154
N(d2)
= 0.23886
C
= 245.92*0.30154 - (295
* e-.06 *0.23886) = 74.155 – 66.360 = 7.795 million.
The
value of the put is then C - P0 + X e-RT = 7.795 –
245.92 + 295*
e-.06
= 36.694 million.
The total NPV of the project after taking into account
the abandonment option = NPV without abandonment option + value of abandonment
option = 5.92 + 36.694 = 45.62 million.
10
a) In the Black-Scholes formula, N(d1) is related to the probability
that the option will be exercised on the maturity date.
T That’s what it represents at an intuitive level.
It’s not mathematically equal to the probability the option will be
exercised, but it roughly corresponds to it.
And higher values of N(d1) represent a higher likelihood of
exercise.
b)
When we use the Black-Scholes formula to value the option to make
follow-on investments, P0 is the PV today of the future NPV of the
follow-on (or second stage) project. F It’s
the PV today of the future PV of the follow-on (or second stage) project.
c)
The option to make follow-on investments is a call option on the future
PV of the first stage project. F It’s a
call option on the future PV of the second stage project.
d)
When the second stage project occurs several years after the first stage
project, we use the standard deviation of annual returns in the Black-Scholes
formula; if the second stage project occurred several months after the first
stage project, we would use the standard deviation of monthly returns. F
In the Black-Scholes formula we always use the standard deviation of
annual returns. (All variables are
measured annually: time to maturity, Rf and σ.)
e)
The timing option is an American call option; it can be exercised before
maturity. T That’s exactly what it is
– we can exercise it either today or tomorrow, not just at maturity.
f)
The timing option is valuable only because waiting may lead to some new
information being revealed before you decide whether to accept the project or
not. T Without new information there would
only be a cost of waiting and no benefit. You
would never wait, and the option to wait would have no value.
g)
The only time an American call option on a dividend-paying stock might be
exercised early (before maturity) is just before an ex-dividend date; the higher
the dividend, the more likely you are to exercise early.
T Any time you exercise before maturity, you lose the time value of
the option, so there is always a cost of exercising early.
There is a benefit to exercising early only just before an ex-dividend
date. By not exercising you lose
the dividend; by exercising you get the dividend.
So you will exercise early only on ex-dividend dates.
And you exercise only when the dividend is greater than the time value of
the option, so the higher the dividend the more likely you are to exercise
early.
h)
The abandonment option is a put option on the PV of the project’s
cashflows; the exercise price is the investment amount.
F It is a put option but the exercise price is the abandonment value
– the after-tax salvage value you get by abandoning the project.